Hi all
How many combinations will I get if I use 6 numbers in combinations of 4. I want to bet 6 horses to win the first 4 but want to see if its cheaper to box them

When order is a distinguishing factor, a group of n members taken r at a time results in a number of permutations equal to the first r terms of the following multiplication:

(n)(n-1)(n-2)...

If this describes your situation, it should be 6x5x4x3.

But, I know very little about horseracing so I am not positive I understand your situation clearly.