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View Full Version : Absolute Maximum & Minimum


donacarol
Oct 21, 2012, 12:50 PM
h(v) = v^2 - 2v + 4 for the closed interval 0 and 5

Curlyben
Oct 21, 2012, 12:52 PM
What do YOU think ?
While we're happy to HELP we won't do all the work for you.
Show us what you have done and where you are having problems..