View Full Version : Composition Functions and Inverse Functions
SpecialK
Mar 7, 2007, 09:53 AM
Wow! These things are boogers! :eek: any way to make these things easier?
xSquishyx
Mar 8, 2007, 02:51 PM
wow! these things are boogers! :eek: any way to make these things easier??
Yes. That is by practicing and practicing and practicing until you get the hang of it.
If your textbook has the odd answers in the back, why not do all of the odd ones.
As you keep doing them, they'll become easier for you.
Hope this helps.
hugheskj
Jun 27, 2010, 01:15 PM
find the inverse of f(x)
f(x)=2x+1/x-3
galactus
Jun 27, 2010, 01:24 PM
Solve for y, by switching the dependent and independent variables.
x=\frac{2y+1}{y-3}
Now, solve for y and you have the inverse.
Rewrite, by using long division, as x=\frac{7}{y-3}+2
Now it is easier to solve for y.
x-2=\frac{7}{y-3}
\frac{1}{x-2}=\frac{y-3}{7}
\frac{7}{x-2}=y-3
y=\frac{7}{x-2}+3
y=\frac{3x+1}{x-2}
This should help you tackle others.