is this correct?!
6x+33+5x=11(x+3)
so
6x+33-33+5x=11x+33-33
6x+5x=11x
what do u do next ?

Slow down there horse.

Start from the beginning and show each stage.
You get MORE marks for the working out then for the actually answer.

So start over.

Kk
So what did I do wrong?

Start from the original equation and do each stage at a time in full.
Least then we can see where there's any mistakes, if any..

The goal is to put numbers on one side and x's on the other
so you get x=Number

k
6x+33+5x=11(x+3)

Where are you getting these from?
Remember you CANNOT have 0x = anything

It does NOT work out.
You must have some amount of x..

from a math book
this is exactly what it says
9. 6x+33+5x=11(x+3)
and u could have x alone it just = 1

OK so lets see what you have step by step..
Actually that ones really dumb!

6x+33+5x=11(x+3)
11x+33=11x+33

So that's just plain stupid..
As x can be ANYTHING you want.
Now you can see why it's important to show all of your workings..

kk
6x+33+5x=11(x+3)
6x+33-33+5x=11x+33-33
6x+5x=11x
is this correct if it is..
what comes next?

Exactly!
Dumb.
Right method, rubbish question..

hu?
so what do u do next?
6x+5x=11x
minus 11-6
5x=5
so the answer is 1?

OK so lets see what you have step by step..
Actually that ones really dumb !!

6x+33+5x=11(x+3)
11x+33=11x+33

So that's just plain stupid..
As x can be ANYTHING you want.
Now you can see why it's important to show all of your workings..

See the problem here?

Oh

hu??
so wat do u do next??
6x+5x=11x
minus 11-6
5x=5
so the answer is 1?


Your mixing things up here.
You can't just drop an x as it messes it up..