Viictoriia94
Apr 19, 2012, 05:03 PM
(2sin(x))/(cos(x)-sin(x)) (2cos^(2)x)/(cos(2x))-(sin(2x 2))/(cos(2x))=0
ebaines
Apr 20, 2012, 07:38 AM
Please verify the equation - what I think you wrote is this:
\frac {2 \sin x}{(\cos x - \sin x)} \times \frac {2 \cos^2 x}{\cos(2x)} - \frac {\sin (2x+2)}{\cos (2x)}
II'm pretty sure the sin(2x+2) is not right. And perhaps there should be a + sign between the first and second terms? But even with these changes the equation doesn't work.