(2sinθ)/(cos2θ-sinθ) (2cos^(2)θ)/(cos2θ)-(sin2θ 2)/(cos2x)=0

The things that look like an I with a comma are supposed to be x's

(2sin(x))/(cos(x)-sin(x))+(2cos^(2)x)/(cos(2x))-(sin(2x+2))/(cos(2x))=0