If you live in a tent whose inside volume is 203 m3 and the temperature in a cold morning is 15.o degree C but becomes 20.0 degees C in the afternonn due to the sun's warming, how many cubic meter of air was forced out of the tent due to the sun's warming . Assume that the pressure in the tent remains constant.

Ideal gas law:

PV = nRT

Here P and V are constant, and R is a constant, so you have


n_1T_1 = n_2T_2


Rearrange to get n_2/n_1. This is the ratio of the number of moles of air in the tent before and after. Then 1-n_2/n_1 = the fraction of air that was forced out. Multiply this by the tent volume to get the number of cubic meters for air that was forced out.

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