Mageshwar
Jan 17, 2012, 03:12 AM
[ area of quadrant of circle whose diameter =3.5cm]-[area of right angled triangle whose base=3.5cm,height=2cm]=area of shaded figure
ebaines
Jan 17, 2012, 07:31 AM
By "quadrant of a circle" I assume you mean 1/4 of the area of the circle. And since there is no picture attached I am assuming that the area of the shaded area you're asking about consists of the area of the quadrant of the circle miunus the area of the triangle.
The area of 1/4 of a circle is A_1 = \frac 1 4 \pi R^2. The area of a triangle of base length B and height H is A_2 = \frac 1 2 B H. So A1 minus A2 is:
A_1 - A_2 = \frac 1 4 \pi R^2 - \frac 1 2 B H
You have values for R, B and H - tell us what you get for a final answer and we'll check it for you.