:confused: does anyone know how to find the magnitude of a vector because I can add and subtract them and all that stuff but I can not find the magnitude and the heading... so if someone could help me that would be nice!:confused:

As Pythagoras' theorem shows: the magnitude of a vector V is
V^2 = V_x^2 + V_y^2

For the heading you need to use basic trigonometry, form a triangle and use the lengths you know to work out the angle you need.

Capuchin's answer is correct but I thought you might like to have it spelled out a bit more.
Lets assume you have a vector V which starts at \left(x_1 , y_1\right) and ends at \left(x_2 , y_2 \right)
\left|V\right| means "magnitude of V"
\left|V\right|=\sqrt {{\left(x_2 - x_1\right)}^2+{\left(y_2-y_1\right)}^2}

The direction can be found like capuchin said, with trig.

Here's the vector V starting at (x1,y1) and ending at (x2,y2).


(x2,y2)
/|
/ |
V/ |dy
/ |
/----|
(x1,y1) dx

dx=x_2 - x_1 \\
dy=y_2 - y_1


Now you want the angle of the vector V. I found this image that will explain what to do. Replace the x and y with the dx and dy you found above. \theta is the angle of V.

http://upload.wikimedia.org/math/5/3/c/53c92cf15a8566cfbd1283c0153a4044.png



As an aside, Capuchin, |V| is the magnitude of V, do you recall what symbol is used for the angle of V? I feel like there is something but I can only recall how to denote the unit vector.

I don't believe there is one, you just use I, j and k, the direction information is there :/