Hi there everyone,

I'm remodeling my bathroom, and I've run into a problem.

I'm using a standard setup for the bath with a dual handle manifold which uses a stop on the tub spigot to divert flow to the shower head, but I've made a decision that has put me at a stopping point.

I've plumbed a standard shower head above the manifold, but I've also plumbed a rain head that exits from the ceiling. I thought it would be easy to find an in wall diverter to direct the flow from the main showerhead to the rain head in the ceiling. Such has not been the case.

I think I could use a standard rotary style manifold, plugging one of the intended outlets, and using the remaining outlet as the inlet, then making the hot and cold my new outlets, but the problems with this is that they're overly expensive for what I'm doing, and also the escutcheons are always labeled for H&C(plus they're usually huge).

I've found diverters like this (http://www.shop4classics.com/product.asp?lid=747), but it's intended to be outside the wall.

Does anyone know of an inwall diverter that I can use for my needs?

Any help would be greatly appreciated.

Thanks,
Json

Hi there everyone,

I'm remodeling my bathroom, and I've run into a problem.

I'm using a standard setup for the bath with a dual handle manifold which uses a stop on the tub spigot to divert flow to the shower head, but I've made a decision that has put me at a stopping point.

I've plumbed a standard shower head above the manifold, but I've also plumbed a rain head that exits from the ceiling. I thought it would be easy to find an in wall diverter to direct the flow from the main showerhead to the rain head in the ceiling. Such has not been the case.

I think I could use a standard rotary style manifold, plugging one of the intended outlets, and using the remaining outlet as the inlet, then making the hot and cold my new outlets, but the problems with this is that they're overly expensive for what I'm doing, and also the escutcheons are always labled for H&C(plus they're usually huge).

I've found diverters like this (http://www.shop4classics.com/product.asp?lid=747), but it's intended to be outside the wall.

Does anyone know of an inwall diverter that I can use for my needs?

Any help would be greatly appreciated.

thanks,
json
This is one I've had great success with. (http://www.absolutehome.com/home/improvements/57348-Grohe-Classic-3-Port-Diverter-Valve-Trim--29733.html)

This is one I've had great success with. (http://www.absolutehome.com/home/improvements/57348-Grohe-Classic-3-Port-Diverter-Valve-Trim--29733.html)

Thanks very much for your reply, but would you happen to know of a less expensive alternative? That exceeds the cost of my whole current setup :)

Thanks,
Json

Well, you could try finding individual volume controls for each individual function.

If you do this, plug the top port of the tub/shower valve and pipe out of the bottom of the valve -- The upper port usually has a flow restrictor in it, which means you'll have greater volume out of the lower port.

I just wanted to say thanks for your help. I found a discontinued version (m# 29734) of the diverter you posted (m# 29733) on eBay which looks to be a 4 port instead of 3 port for about half price. If I'm right that it's a 4 port, I'll simply use it for the spigot as well as the heads. Visually, it's identical.

Thanks again!
Json

Hi there iamgrowler, I have the diverter now, and have a couple more questions for you, if you're still around:

1) How is it mounted? There are no mounting flanges or flat spots on the valve body. Does it just float inwall, using only the escutcheon to hold it in place?

2) There are four ports on the valve. One 1/2 inlet, and right across from that, and outlet that works regardless of the position of the valve, then there are two outlets perpendicular to the inlet. I understand that the tub spigot should be on the one across from the inlet, as stopping the spigot will supply the water to the other two outlets, but what confuses me is that of the two remaining outlets, one has a 3/4" outlet, and the other is 1/2". Can I just reduce that down to 1/2"?

http://www.schwimhosting.com/Hosting_CP/out.php?i=1798_valve1.jpg
http://www.schwimhosting.com/Hosting_CP/out.php?i=1797_valve2.jpg
http://www.schwimhosting.com/Hosting_CP/out.php?i=1796_valve3.jpg

Thanks,
Json