I attach the Pdf Math File which is shown as below. Please Open it and Solve my Problem...?
Please tell me as soon as possible.
Thanks a lot for this....1

It is the same, x=-(t+1) or x=-t. Personally I would have put x=-t.

If you replace x with -t you get:


\lim_{t \to \infty} (1 - \frac 1 t )^{-t}
= \lim_{t \to \infty} (\frac t {t-1} )^{t}


Not sure how to proceed with that. But if you replace x with -(t+1) you get:


\lim_{t \to \infty} (1 - \frac 1 {t+1} )^{-(t+1)}
= \lim_{t \to \infty} (\frac t {t+1} )^{-(t+1)} = \lim_{t \to \infty} (\frac {t+1} t)^{(t+1)}= \lim_{t \to \infty} (1 + \frac 1 t)^{(t+1)}


which was already shown to equal e.

With x=-t you get

\lim_{t\rightarrow +\infty} (\frac{t}{t-1})^t =
\lim_{t\rightarrow +\infty} (1+\frac{1}{t-1})^t=
\lim_{t\rightarrow +\infty} ((1+\frac{1}{t-1})^{t-1})^{\frac{t}{t-1}}