2*(sin^(6)θ cos^(6)θ)-3*(sin^(4)θ cos^(4)θ) 1=0
need to verify this identity

Please be aware that you can't copy and paste special characters such as \theta (theta) into this web site, or it ends up looking like gibberish. Please type the equation out, or use the Latex facility. However, I think this may be what you mean:


2(\sin^6x + \cos^6x) - 3(\sin^4x + \cos^4x) + 1 = 0


If you replace \cos^6x with (1-\sin^2x)^3 and replace \cos^4x with (1-\sin^2x)^2 and then do the algebra, it falls right out.

Cos^2(2u)-sin^2(2u)

cos(4u)=cos^2(2u)-sin^2(2u)