The gravitational force of attraction between two students sitting at their desks in physics class is 2.33 10-8 N. If one student has a mass of 47.0 kg and the other student has a mass of 57.0 kg, how far apart are the students sitting?

Please show step by step works, thanks

The gravitational force of attraction between two students sitting at their desks in physics class is 2.33 10-8 N. If one student has a mass of 47.0 kg and the other student has a mass of 57.0 kg, how far apart are the students sitting?

Please show step by step works, thanks


Hi sh1


You will need to know Newton's universal law of gravitation.

Newton's law of universal gravitation - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Newton's_law_of_universal_gravitation)

this is your equation
Fg = G{m1 m2}/{r^2}

plug in the things that you know.
Fg=2.33e-8
G=6.67e-11
m1=47
m2=57
r=?

make the equation equal to r

r^2=G{m1 m2}/{Fg}

r^2=(6.67e-11*47*57)/2.33e-8

r^2=7.67

take the square root of that number

r=2.77

the distance is 2.77m