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View Full Version : Clear my doubts in chemistry


mrudula
Jul 25, 2011, 06:49 PM
Mg forms mg(11)because of

jcaron2
Jul 25, 2011, 07:52 PM
I have no idea what mg(11) means! Can you provide some context? Are you talking about atomic weight (which doesn't make sense since Mg has 12 protons - no way that any amount of fission is going to yield Mg11)? Or maybe those are Miller indices for a crystallographic orientation (which also doesn't make sense since Mg is a hexagonal structure, which means it should have four Miller index numbers, not two)? Maybe this is just some nomenclature I'm not familiar with, but I'm definitely confused. :confused:

DrBob1
Jul 25, 2011, 08:52 PM
I'm sure the question refers to the formation of the Mg+2 ion. Sounds like homework, but here's a hint: Why does Magnesium occupy its particular spot on the Periodic Table?

mrudula
Jul 30, 2011, 07:26 PM
They gave the options also 1)0.5 2)2.5 3)1.5 4)3.5
And give the reason also

mrudula
Jul 30, 2011, 07:29 PM
They had gave the options also they are 1)0.5 2)2.5 3)1.5 4)3.5

jcaron2
Jul 30, 2011, 08:00 PM
Mrudula, was there more to the question that you didn't post? Like maybe some more description or a figure to go with it or something? It doesn't seem possible that the answer to your original question would be a number. ;)

DrBob1
Jul 30, 2011, 08:11 PM
Mrudula
This now makes so little sense that I have to believe that you must have misread or miswritten the question.
You give four choices less than 4 and also 11 -- huh?
Why something is formed can't be answered by numbers.
Try again.

raj1996
Mar 8, 2013, 11:52 PM
Sinmply for fun

raj1996
Mar 8, 2013, 11:54 PM
Pembrokes

srikanth2529
Jun 29, 2013, 10:28 AM
2 moles of he and 1 mole of ch4 is taken inside a container, which is made effused through a small orifice of container having same area of cross section at the same temperature, then which is the correct effused volume percentage of he and ch4 initially respectively?
The options are A. 80%, 20% B. 20%, 80% C. 30%, 70% D.40%, 60% please give me detailed solution regarding this question.