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saadsaad
May 29, 2011, 11:18 PM
{tan (pi / 2 - x ) sec x } / 1-csc^2 x

RickJ
May 30, 2011, 09:38 AM
What is your question?

ebaines
May 31, 2011, 06:51 AM
saadsaad - if your question is how to simplify this, try replacing the tan, sec, and csc functions with their sine and cosine primitives. And recall that sin(pi/2-x) = cos(x), and cos(pi/2 - x) = sin(x).