An ideal gas in tank - (minus) 30 F initial temperature is allowed to expand quickly into a larger empty tank. If the volume of the gas in increased from 5000 cm^3 to 25 liters and the pressure is reduced from 8 atm to 2.02 * 10^5 Pa, what is the new temperature of the gas?

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1. Make sure all the values are in the correct units, i.e. temperature in kelvin, pressures have the same unit and the volumes have the same units.

2. Use:

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

Post what you get! :)