sin^6(x) + cos^6(x) = sin^4(x) - sin^2(x) * cos^2(x) + cos^4(x)

How do you think you should start?





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Look at the factorization for the sum of two cubes.

Factor:

a^{3}+b^{3}

Let a=sin^{2}(x), \;\ b=cos^{2}(x)