I asked to find the number of Valence electron in Bismuth so my answer is 5. yes?

And 1 more question is I need to find the number of electrons in 4th level of Au
So is will be 32? Because if we look on Au in the 4th level so there 2 electrons in 4s 6 electrons in 4p 10 electrons in 4d and 14 electrons in 4f

Do I correct in my answers ?

Thanks.

I would say yes :)

hi.
thank you for answer.
so if I asked to find the number of Atomic orbital of: principal quantum number(n) and the orbital Angular momentum quantum number (L) of the orbital 2s


tell me if I correct n=2 and the Angular momentum L=0 ?

and in the orbital 6f n=6? And L=3?

thanks.

Sorry, this time it's really beyond me :(

:) that OK still thank you for all your help.

hi.
thank you for answer.
so if i asked to find the number of Atomic orbital of: principal quantum number(n) and the orbital Angular momentum quantum number (L) of the orbital 2s


tell me if i correct n=2 and the Angular momentum L=0 ?

and in the orbital 6f n=6? And L=3?

thanks.

Pop, your answers are correct, but be careful. The azimuthal quantum number (also known as the orbital angular momentum quantum number) is usually denoted with a small cursive \ell. Capital L is usually reserved for the angular momentum, itself (or the orbital angular momentum operator in Schrodinger's wave equation), not the quantum number.

yes truth I mean L=l.
thank you. :)