The Beta plans a dance as a fund raiser. The band cost $650, decoration cost $45 and the refreshment cost $2.20 per person. The admission tickets are $6 each.

What is the linear cost function
The revenue function
The profit function
How many tickets must be sold to break even
How many tickets must be sold to clear $700

What have you tried so far?

What are the costs, and what are the revenue?

Recall that profit is the difference between the revenue and the cost.

The Beta plans a dance as a fund raiser. The band cost $650, decoration cost $45 and the refreshment cost $2.20 per person. The admission tickets are $6 each.

What is the linear cost function
The revenue function
The profit function
How many tickets must be sold to break even
how many tickets must be sold to clear $700

Am I on the right track?
Y=C(X)=mx+b

(x2, y2) = (650, 45)
(x1, y1) = (2.20, 6)

650-45=605 = 159.2
2.20-6=3.8

Unfortunately no. The values given to you are not coordinates, they are constants, and some are associated with variables.

Costs = Band + Decoration + Refreshment.
Band is constant, $650
Decoration is constant, $45
Refreshment is $2.20 per person. Let the number of persons be x. Total cost for refreshment = 2.2x

Total cost = 650 + 45 + 2.2x = 695 + 2.2x

This is the cost function, or

C(x) = 695 + 2.2x

Now, the admission tickets is the source of revenue. Can you work out the total revenue with x people for $6 per person?

Then the profit function is given by the Revenue function minus the Cost function.

Break even is the case Profit = 0. Do that, and solve for x.

This time, the profit is $700, equate the profit equation to $700 and solve for another x.

Can you post what you get? :)

e) 2