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View Full Version : -6m - [n to the third power]; m=-3, n=-2


demetriusbrown
Feb 7, 2011, 03:43 PM
What is the answer to this problem and show how you got it.

ebaines
Feb 7, 2011, 03:52 PM
Do you mean this:


-6m-n^3


where m = -3 and n = -2?

If so, then when you do the substitution you get:


-6 (-3) - (-2)^3 = 18 -(-2\ \times \ -2 \ \times \ -2) = 18 -(-8) = 18+8 = 26