6cos (x 45) = 5

give all possible angles

Is the equation this?

6 \cos(x+45) = 5

Divide by 6 first to get;

\cos(x+45) = \frac56

Then, find the critical values, that of \cos(\alpha) that gives 5/6.

If the limits weren't specified, you use a variable '360n' and express your answer.

For example, one set of answers is:

33.6 +360n

for alpha.

Then, for x, it becomes:

33.6 - 45 + 360n = 360n - 11.4