View Full Version : 2^2^2^2^2... For primes
dfsacxzsdefa
Nov 20, 2010, 08:56 PM
Let's say we are given the numbers 2, 2^2, 2^(2^2), 2^(2^(2^2)), and so on. Would all these numbers plus one be a prime number? (So far I see that 2^(2^(2*2)) or 2^16 works, but sadly 2^65536 is a little harder)
galactus
Nov 21, 2010, 07:10 AM
No, they are all not primes.
i.e 2^{256}-1 is not prime.
But, Mersenne primes have the form
2^{p}-1, where p is prime.
See here:
The UCLA Mersenne Prime (http://www.math.ucla.edu/~edson/prime/)
Unknown008
Nov 21, 2010, 08:45 AM
Um... it's 'plus' one and not minus one... but then, I don't know...
Wolfram alpha gave the digit as a 19729 digit number :eek: