Let f(x)=(x^2-1)(e^x-1). Find the value of x which give f(x)=0. [Archive]

View Full Version : Let f(x)=(x^2-1)(e^x-1). Find the value of x which give f(x)=0.

modesty07

Nov 7, 2010, 08:41 PM

ebaines

Nov 8, 2010, 07:13 AM

If either the term (x^2-1) = 0, or (e^x - 1) = 0, then f(x) = 0. This means that either of the following conditions yield f(x) = 0:

x^2 = 1, or
e^x = 1.

Can you take it from here?