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View Full Version : How many ordered pairs of integers (x,y) are there such that 0 < |xy| '‰ 5?


Loloo
Oct 15, 2010, 11:49 AM

Unknown008
Oct 15, 2010, 11:58 AM
Could you repost the last symbol or say what it is?

Loloo
Oct 15, 2010, 12:05 PM
It means less or equal to 5

Loloo
Oct 15, 2010, 12:08 PM
It means less or equal to 5

Unknown008
Oct 15, 2010, 12:56 PM
I'm not sure how to go about it with strict calculations, but with guesswork, we can get them all.

-1 and -5 and vice versa
1 and -5 and vice versa
-1 and 5 and vice versa
1 and 5 and vice versa

That's it :)

EDIT: Now, you need to look for those pairs which form less than 5.

Which are (1|1), (1|2), (2|2), (1|3), (1|4) pairs with plus and minus signs.

This makes some more pairs to add.

kpg0001
Oct 15, 2010, 01:04 PM
What about (1,4),(1,3),(1,2),(1,1),(2,2) with all the -/+ and vise versas? I mean the only rules are that when multiplied together the absolute value has to be greater than zero but less than or equal to 5 right? And that is just whole numbers. In reality there is an infinite number of pairs that could fit. Am I missing something?

Unknown008
Oct 15, 2010, 11:04 PM
Yes, I'm the one who missed something. After a good night of sleep, I realised my mistake but you had already posted before I was able to come online :o