Find e/m for electrons in an experiment in which H=2.68 gauss, S=5.00 cm, E=6.3x10^10 volts/cm, and 0=0.100 radian.

The 0 in 0-0.100 is really a 0 with a line through it

Thanks again

I have another question it you can't answer the above one.
What magnetic field strength is required to bend the path of a singly charged neon-20 atom (mass-19.992 440 u) through 0.500 radian if the path length is 10.0 cm? Assume that velocity is 2.20x10^8 cm/s, 1 u-1.66x10^-24g, and e=1.602 189 2x10^-19 coulombus. What electric field strength would be required to obtain the same result?

2.

Is 10.0 cm the arc length of the path? If so, use s = r\theta

r = \frac{s}{\theta} = \frac{10}{0.5) = 20\ cm

Now, F = Bev and F = (mv^2)/r;

Bev = \frac{mv^2}{r}

B = \frac{mv}{er} = \frac{(3.31874504\times 10^{-23})(2.20\times10^8)}{(1.6021892\times10^{-19})(20)

When you get that, find F for F = Bev.

Then, in an electric field, you will need to have a radial field with the same force, or

F = Ee

where E is the electric field strength.
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For the first one, I have no idea of what you're talking about.