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View Full Version : Calculate: Heating 235 g of water from 22.6 degrees C to 94.4 degrees C in a microwav


blackpalm
Sep 15, 2010, 06:39 PM
I guess we must use c=lambda*frequency...

Unknown008
Sep 15, 2010, 10:38 PM
Actually... no.

c = f\lambda

is used to find the frequency or wavelength of an electromagnetic wave if either the wavelength or the frequency is known.

Here, I guess that you are looking for the amount of heat that the water gains.

This is given by:

Q = mc\theta

Q is the amount of heat in joules
m is the mass of the substance
c is the specific heat capacity of water (which you must be given)
and theta is the change in temperature in Kelvin.

Can you work this out now? :)