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View Full Version : How do I write the standard form equation of the circle -6y= -x^2-16x-y^2-72


bre07
Aug 22, 2010, 01:01 PM
Please show the work so I can understand

galactus
Aug 22, 2010, 01:51 PM
Bring everything to the left side, but leave the -72

x^{2}+16x+y^{2}-6y=-72

Group x's and y's, then 'complete the square' by adding the square of half the coefficient of x and y.

(x^{2}+16x+64)+(y^{2}-6y+9)=-72+64+9=1

Factor each group:

(x+8)^{2}+(y-3)^{2}=1

That's it. It has center (-8,3) and radius=1

stedan01
Aug 26, 2010, 02:40 PM
50-2x10+4

galactus
Aug 28, 2010, 08:35 AM
50-2x10+4

Straighten up.:rolleyes: