3 x + y = 243
2x – y = 1

3 to the power of x + y (not 3 x + Y) = 243
and 2x - y = 1 (not to the power of)

3^{x+y} = 243

2x - y = 1

From the first equation, you can rearrange by taking logs on both sides.

log(3^{x+y}) = log(243)

Using the power law, we get:

(x+y)log(3) = log(243)

Now, divide by log(3);

x+y= \frac{log(243)}{log(3)}

x+y= 12

Now that you got two linear equations, can you work the rest out?

I hope it helped! :)

Thanks hey! Jip got it now!

No problem :)