The equation for the metabolic breakdown of glucose (C6H12O6) is shown
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l)
Calculate the volume of CO2 produced at 37 °C and 1.00 atm when 5.60 g glucose is used up in the reaction.

1. Find the number of moles of glucose used up. (Use mass/relative mass = number of moles)

2. Find the number of moles of carbon dioxide produced from the number of moles of glucose found in 1.

3. Find the volume of that carbon dioxide using the ideal gas equation; PV = nRT

Post your answer! :)