jillksantucci
May 5, 2010, 10:35 PM
I need help simplifying log2 x = -1
Unknown008
May 6, 2010, 12:43 AM
I guess you mean solving:
log_2\ x = -1
?
Then, you need to know that if:
log_a\ b = c
then;
b = a^c
Can you try it now? Post your answer! :)
The long way round is:
log_a\ b = c
\frac{log\ b}{log\ a} = c
log\ b = c log\ a
log\ b = log\ a^c
b = a^c