saywhat235
May 4, 2010, 07:02 PM
Given x~B(20,0.6). Find P(X> or equal to 18).
galactus
May 5, 2010, 10:48 AM
\sum_{18}^{20}C(20,k)(.6)^{k}(.4)^{20-k}
Unknown008
May 5, 2010, 11:18 AM
Or if you prefer in that format, which you then simplify:
P (X \geq 18) = P(X = 18) + P(X = 19) + P(X = 20)