View Full Version : Organic chemistry eperts are their any on this site
curosity
Feb 17, 2010, 09:58 AM
Acid and bases.. how would I increase the output of a vinegar and baking soda type experiment
Unknown008
Feb 17, 2010, 10:03 AM
I'm having a little trouble understanding your problem.
There is the reaction:
CH_3COOH + NaOH \rightarrow (CH_3COO)Na + H_2O
Then, what are you trying to do? What do you mean by increasing the output? The yield you mean?
If that is so, the reaction is quite a fast reaction where all the reagents react (except if one is in excess) to form the products.
EDIT: Oops, I put in sodium hydroxide instead of sodium carbonate... sorry for that mistake...
curosity
Feb 17, 2010, 04:18 PM
Sorry about the vague question I didn't really expect anyone to respond but here's the situation;
I have a lab project in my head that I have no idea on how to make work, if it is even possible:
Its similar to the classic vinegar and baking soda experiment.
My dilemma is that I need to inflate a 7inch ballon almost to the point of popping,
vinegar/baking soda gives me expansion but not nearly enough... another shortfall of the vinegar/baking soda combination is that the vinegar/soda mix turns into
Mush and destroys other elements of my project.
My question is in chemical reactions:
Question: Is their a cleaner solution (Acid/Base)to produce this effect and not leave the mushy byproduct?
A different chemical mix or something? Non hazardous of course
Unknown008
Feb 18, 2010, 08:49 AM
I never did such an experiment, but that's how I think I would do it.
7 in diameter is 3.5 in radius. So, roughly the volume is 4/3 * pi * 3.5^2 = 51.3 in^3.
Since 1 464 cubic inch (I converted it from 24 litres) of gas at 25 C (I'm assuming room temperature to be 25 C) contains 1 mol of gas, 51.3 cubic inch will contain about 0.035 mol of gas.
0.035 mol of CO2 is required then.
From the reaction:
2HCl + Na_2CO_3 \rightarrow 2NaCl + H_2O + CO_2
You need 0.035 mol of Na2CO3, which has a mass of (0.035*106) = 3.71 g.
So, you will need to weigh 3.71 g (plus minus 0.05 g) and mix it with the acid, not matter the concentration, but be sure that the acid is in excess and that no gas escapes during the process.
This is an example from what I know. You may use another acid... or perhaps use sodium hydrogen carbonate, which will give the same volume of carbon dioxide for less mass of reagent.
curosity
Feb 19, 2010, 07:56 AM
Thanks this is the most help I've gotten on this topic. Using this info I'll try to work through this. I am at a disadvantage, I know nothing about the subject. Practical application/trial and error all the way
Unknown008
Feb 19, 2010, 08:49 AM
You're welcome! :)