View Full Version : Graph 2csc(2x)
CATSDOGS
Feb 11, 2010, 02:45 PM
I need help on trigonometric functions! I don't understand, I'm getting mad, I have no clue what to do or where 2 start. i need help!!!
bulksalty
Feb 11, 2010, 02:51 PM
normally graphs are made by entering a few points until you can see a curve forming.
So you'd pick some values for x (good choices are -2, -1, 0, 1, 2) and find out what y would equal (in your example that means plugging in each of these values into your equation so for the first it's 2*-2 then find the cosecant of that, then multiply that by 2 and plot the point. Repeat for the other 5 points.
However, what you'll find is that as you expand outward there will be points where the function becomes undefined, and after those points the y values will flip. Cosecant and secant functions look like big letter U s alternating between Us that are right side up and Us that are up side down.
galactus
Feb 11, 2010, 04:20 PM
You don't have a graphing calculator? Remember, csc(2x)=1/sin(2x).
sin(2x)=0 when x=\frac{C{\pi}}{2}, therefore, that is why the graph heads toward infinity when x is a multiple of Pi/2. Let C=... -3,-2,-1,0,1,2,3,.