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cmasonnyc
Jan 4, 2010, 10:13 PM
Each person contributes $5 to purchase 2 items and had $1 left over. If the same number of people contribute $8 and can purchase 3 items and have $11.50 left over, how many people are contributing?

Clough
Jan 4, 2010, 11:06 PM
Hi, cmasonnyc!

Are you looking for someone to directly answer your question, or for someone to show you how to come up with the answer yourself, please?

If the former is what you want, then please click on the following link to read the Announcement there.

https://www.askmehelpdesk.com/math-sciences/announcement-font-color-ff0000-u-b-read-first-expectations-homework-help-board-b-u-font.html

Thanks!

Unknown008
Jan 5, 2010, 08:10 PM
Well, the is only one thing you don't know, and that's the price of the item.

So, let it be 'x'.

2x + 1 = 5

'Twice the price of an item, added to the remaining one dollar makes 5 dollars'.

Now, you can solve for x and proceed with the rest of the question.

ROLCAM
Jan 7, 2010, 05:50 AM
The number of people contributing
is 20.

Proof A = (20*5) - 1 = 99/2 = 49.50 each

Proof B = (20*8) -11.5 = (160 -11.50) = 148.50/3 = 49.50 each

Unknown008
Jan 7, 2010, 09:05 AM
Well, the is only one thing you don't know, and that's the price of the item.

So, let it be 'x'.

2x + 1 = 5

'Twice the price of an item, added to the remaining one dollar makes 5 dollars'.

Now, you can solve for x and proceed with the rest of the question.

Sorry, I made a really silly mistake here. I was in too much of a hustle to see the whole question :o

Yes, you have got the first equation, that is :
5x = 2y + 1

where x = number of people and y the price.

For the second piece of information, it's similar:

8x = 3y + 11.5

You only need to solve them simultaneously and you're done.

Rolcam already got the answer. :)