(1L)(1.25mol/0.35L)(40g/1mol)=142.86g

I really hope This is corret :p:confused::eek:

Is it correct?

Thank you~!~!~

Well, I never do these on a line...

Ok, here's how I do it:

350 mL of 1.25 M = (1.25*350)/1000 = 0.4375 mol
0.4375 mol -> 0.4375*40 = 17.5 g

Ok, if I examine your work, you should multiply volume and concentration and mass. So, 0.35L\ \times \ \frac{1.25mol}{1L}\ \times\ \frac{40g}{1mol}

OK you want to know gramwt of NaOH for 1.25M concentration of 35 mL volume
OK
M=1.25
molecular wt=40
formula is
M=gmwt*acidity/molecularwt*volume in L
so GMWT=M*molecularwt*volume in mL/acidity*1000

1.25*40*350/1*1000
=17.50 gm requaired I confidentially

:p
Well, I never do these on a line...

Ok, here's how I do it:

350 mL of 1.25 M = (1.25*350)/1000 = 0.4375 mol
0.4375 mol -> 0.4375*40 = 17.5 g

Ok, if I examine your work, you should multiply volume and concentration and mass. So, 0.35L\ \times \ \frac{1.25mol}{1L}\ \times\ \frac{40g}{1mol}

Yes , so answer is 17.5g right?

Thanks