KISS
Sep 28, 2009, 07:02 PM
Count the x's = 12 + (-4)
Count the numbers: -10 + -54; move the 54 to the other side
8x-64 = 0; take it from there.
Moving stuff around is just an exercise in futility and stuff gets misplaced.
Unknown008
Sep 29, 2009, 07:28 AM
I do it this way, just in case you can more understand the way I do...
12x - (4x+ 10) = 54
Expand the brackets. To do this, multiply the negative sign with each of the terms in brackets:
12x - 4x- 10 = 54
Now, group the terms in x and without x on one side, say the ones with x on the left side and the ones with no x on the right side. To do this, add 10 to both sides:
12x - 4x\cancel{- 10+10} = 54+10
12x - 4x = 54+10
Now, work this out:
12x - 4x = 54+10
8x = 64
Can you continue now?