langerhanz747
Sep 22, 2009, 07:15 PM
A frog jumps vertically upward from a 20m tall building with an initial velocity of 10m/s.
How high above the ground will the frog reach?
How do you set up this problem
Unknown008
Sep 23, 2009, 09:45 AM
Use your motion formulae.
Here, you make use of v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = displacement.
Taking the upward direction as positive;
u = +10m/s
v = 0 m/s (when it reaches the max height, it is temporarily at rest)
a = -9.81 m/s^2 (downward direction explaining the -ve sign)
s = displacement (the one you're looking for)
Solve for s, and you're done! :)
I hope it helped! :)