If f(x)= the square root of x, g(x)= 6x-3, and h(x)= x/3

what does f(g(h(6))) equal? And how do you do this?

Ok;

f(x)=\sqrt x

g(x) = 6x-3

h(x)=x\sqrt 3

To solve for f(g(h(6))), you need to find the value for h(6) first. To do that, replace the 'x' in h(x) by 6.

You'll have:

h(6) = 6\sqrt3

Now, you need to find g(h(6)). This s done by replacing the 'x' in g(x) by the value of h(6):

g(6\sqrt3) = 6(6\sqrt3) - 3

Can you continue? :)

Post the final answer if you please.

Thanks! I got a 100 on my test today :)

Hey Congrats! :) I was glad to help! :)