Simplify with positive exponents..
5x^3y^6 under radical sign
divided by 3a^3

Do your own homework...

Is this it: \frac{\sqrt{5x^{3}y^{6}}}{3a^{3}}?

If so, there is not much to be done---except look at the y term.

you so would it be y^3 * y^3?

Yes, and that is (y^3)^2, which is under a radical. You can do something with sqrt{(y^3)^2}
Think about it.

2 squared radical y?I'm not sure

no wudnt it just be y^3?

no wudnt it just be y^3?

Yup. :-) The square root of a squared number is just that number.

Remember that you have to pull that out from under the radical since you took the square root of it. But I don't see anything further you can do to the rest of it.

is xy^2 5 under radical sign over 3a^3 right?

You could write it as \frac{\sqrt{5x^{3}}y^{3}}{3a^{3}}

Remember that \sqrt{y^{6}}=(y^{6})^{\frac{1}{2}}=y^{3}

Not much can be done with the x^3 inside the radical. That is the same as \sqrt{x^{3}}=x^{\frac{3}{2}}, so just leave it alone.

Actually, if we were to be purists, the actual form would be:

\frac{\sqrt{5x^{3}}\cdot |y^{3}|}{3a^{3}}

But I do not believe it is necessary to introduce the absolute value, though technically, it belongs there.

OK thnks 4 your help =)