I have to solve this linear equation with 3 variabes:

x-2y=1
x+3y+z=0
2x-2z=18

answer has to be in (x,y,z) formation... please help

Use elimination method or substitution method. Here is elimination:

x-2y=1
x+3y+z=0
2x-2z=18

Multiply the second row by 2:

x-2y=1
2x+6y+2z=0
2x-2z=18

Now, add it to the third row:

x-2y=1
4x+6y=18

That eliminated z.

Now, Multiply the first row by -4:

-4x+8y=-4
4x+6y=18

Add to the second row:

14y=14

y=1

Now, back substitute to find x and z.