Please help me find the derivative of...
y = sqrt of log x

the answer that I got is:
log e/sqrt of log x

thank you!

Do you want to do this from scratch? It's normally not necessary, but cool if you would like to see it.

Remember the chain rule. Which is basically the derivative of the outside times the derivative of the inside.

\frac{d}{dx}[\sqrt{log(x)}]=\underbrace{\frac{1}{2}(log(x))^{\frac{-1}{2}}}_{\text{outside}}\cdot \overbrace{\frac{log(e)}{x}}^{\text{inside}}

=\frac{log(e)}{2x\sqrt{log(x)}}