(x-9)^2=-(y+8)?

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Know that (x-h)^{2}=\pm 4p(y-k)

where (h,k) are the coordinates of the vertex.

p is the distance between the focus and vertex or between the vertex and the directrix.

If the sign is negative, then it opens in the negative y direction.

In this case, 4p = -1. You can easily find p now and the focus and directrix from the vertex coordinates.