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Nargis786
Jun 14, 2009, 01:06 PM
The annual world consumtions of coal and oil over the last 20 years of this century have been and are projected to be as follows:

Coal - (1980) - 3150, (1985) - 3830, (1990) - 4660, (1995) - 5150, (2000) - 5680

Oil - (1980) - 3910, (1985) - 3810, (1990) -3710, (1995) - 3530, (2000) - 3320

All nummbers are in megatonnes of coal equivalent.
It is suggested that the consumption of coal is rising exponentially. Explain how you would test this statement.
Account briefly for the decline in oil consumption and indicate how this decline may be expected to be shared between developed and developing countries.

Perito
Jun 14, 2009, 02:32 PM
if the consumption is rising exponentially, you will see

Consumption = T^x

log(consumption) = xLog(T)

So, if you plot log(consumption) against log(T), you should get a straight line. The slope of the line is the exponent.

Nargis786
Jun 14, 2009, 03:22 PM
if the consumption is rising exponentially, you will see

Consumption = T^x

log(consumption) = xLog(T)

So, if you plot log(consumption) against log(T), you should get a straight line. The slope of the line is the exponent.

sorry i do not understant this fully, please would you be able to explain it further

Perito
Jun 14, 2009, 04:01 PM
Just do the plot (log(consumption) against Log(time)) and see if the graph is linear. You'll understand when you see it.

Nargis786
Jun 14, 2009, 04:11 PM
sorry i do not understant this fully, please would you be able to explain it further

OK thank you I understand now. However I also posted something on u-values and another post with the title energy, power, latent heat and specific heat capacity. Please can you help me on those

Perito
Jun 14, 2009, 04:14 PM
I'm not familiar with the "u-value" terminology. Does u=1/R?

Nargis786
Jun 14, 2009, 04:17 PM
I'm not familiar with the "u-value" terminology. Does u=1/R?

I am not really sure about this myself. Can you just help me on the other post I asked about please which is energy, power, latent heat and specific heat capacity
if you are not able to do the u-value. Thank you