View Full Version : Vertex, focus, and directrix of parabola
bscott0890
Jun 2, 2009, 10:40 AM
How do I find the vertex, focus, and directrix of a parabola?
Unknown008
Jun 2, 2009, 10:44 AM
Arrange your equation in this form:
(x-h)^2=4p(y-k)
or
(y-k)^2=4p(x-h)
The vertex is (x,k); the focus is (h, k+p); the directrix is y=k-p where p is the distance from the vertex to the focus.
You can also search;
Parabola - Wikipedia, the free encyclopedia
Perito
Jun 2, 2009, 10:46 AM
Basically, you put your equation into a general form.
\left(x-h^2\right)=4p\left(y-k\right) \text { axis parallel to the Y-axis}
or
\left(y-k^2\right)=4p\left(x-h\right) \text{ axis parallel to the X-axis}
vertex = (h,k)
focus = (h,k + p)
directrix y = k − p. p is the distance from the vertex to the focus
Link to: Parabola - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Parabola)