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salamander5
May 27, 2009, 12:18 PM
What kinds of things does algebra II involve?

Perito
May 27, 2009, 02:39 PM
It's similar to what was discussed in Algebra I, but more advanced (is that obvious, or what?). I remember learning how to solve for exponents, how to solve quadratic and cubic equations (are those handled in Algebra I?), functions.

Here's a page I googled: ClassZone - Algebra 2 (http://www.classzone.com/books/algebra_2/index.cfm) that contains this table of contents:

Chapter 1: Equations and Inequalities
Chapter 2: Linear Equations and Functions
Chapter 3: Systems of Linear Equations and Inequalities
Chapter 4: Matrices and Determinants
Chapter 5: Quadratic Functions
Chapter 6: Polynomials and Polynomial Functions
Chapter 7: Powers, Roots, and Radicals
Chapter 8: Exponential and Logarithmic Functions
Chapter 9: Rational Equations and Functions
Chapter 10: Quadratic Relations and Conic Sections
Chapter 11: Sequences and Series
Chapter 12: Probability and Statistics
Chapter 13: Trigonometric Ratios and Functions
Chapter 14: Trigonometric Graphs, Identities, and Equations

rashondae
May 28, 2009, 08:19 AM
What is the slope-intercept formof the line x+5y=3?

Perito
May 28, 2009, 08:51 AM
Please post new questions in new threads.

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y=mx+b\,\, is the standard form of a line. This is how to get your equation in that form:

In the above equation, m is the slope and b is the y-intercept.

x + 5y = 3

5y = -x + 3

y=-\frac 15 x + \frac 35 =- 0.2x + 0.6

Can you read the slope and the intercept from this equation?

Unknown008
May 28, 2009, 08:53 AM
Hi rashondae! Welcome to AMHD! :)

Firstly, you have to start a thread of your own rashondae. It's OK for this time, since you are a newbie.

For your question, I don't know about it... I know the y and x intercepts. Just arrange your equation in the form y = mx + c, you'll have m as the gradient, c as the y intercept. If you want the x intercept, set y to zero and solve for x.