I tried to do it multiple times but fractions always gets me frustrated :confused:

P(y)=y^2-4y+3
P(-/4)

This is as far as I got

P(y)=(-1/4)^2-4(-1/4)+3

I tried to do it multiple times but fractions always gets me frustrated

P(y)=y^2-4y+3
P(-/4)

This is as far as I got

P(y)=(-1/4)^2-4(-1/4)+3


P(y)=y^2-4y+3

What is P(-4)?

P(y)=(-4)^2-4(-4)+3 = (-4 \times -4) -(4 \times -4) + 3

P(y)=16 - (-16) + 3 = 16+16+3=35

What is P(-1/4)?

P(y)=(-\frac 14)^2-4(-\frac 14)+3 = \frac {1}{16} + 1 + 3

P(y)=4\,\frac {1}{16}=4.0625