Help! For the life of me I can't figure out how to get the quadratic equation out of this.:confused:

A jet flew from Tokyo to Bangkok, a distance of 4800 km. On the return trip, the speed was decreased by 200 km/h. If the difference in the times of the flights was 2 hours, what was the jet's speed from Bangkok to Tokyo? (13 marks)

Thanks in advance

First of all, let's introduce the unknown terms;

let the speed from Tokyo to Bangkok be x
On the return trip, the speed will be x-200

Speed=\frac{Distance}{Time}

Time=\frac{Distance}{Speed}

So,

\frac{4800}{x} + 2 = \frac{4800}{x-200}

Can you solve it from here?

First of all, let's introduce the unknown terms;

let the speed from Tokyo to Bangkok be x
On the return trip, the speed will be x-200

Speed=\frac{Distance}{Time}

Time=\frac{Distance}{Speed}

So,

\frac{4800}{x} + 2 = \frac{4800}{x-200}

Can you solve it from here?

Yes I think I've got it from there. I was getting stuck on what to write for the time, but that makes sense, thanks!

No, that's OK. I was glad to help! See you around! :)