Determine the number of ions produced on the dissociation of the compound listed.

CaCl2


BaS


CaO


Al2S3


I know AlF3 is 3 but I don't understand that really
However I understand KCl and NaF

What is it with AlF3?

AlF3\, \rightleftharpoons\, Al^{+3} + 3F^-

You actually formed four ions - one Al(+3) and 3 F- ions.

It works pretty much the same way with the other compounds in your list.

Look at the periodic chart to figure out the charge on the ion. K and Na are from group 1A, so they tend to form +1 ions. Group 2A tends to form +2 ions, Group 3A tends to form +3 ions.

At the other end, Halogens (group 7A) tend to form -1 ions; group 6A tends to form -2 ions.

Post your work and we'll tell you if you're correct.

I thought you were talking of the number of moles of dissociation... Like HCl dissociated readily in water so as to produce a strong acid but not ethanoic acid, which dissociates less readily , forming a weaker acid. Ok, If that was the question, then, it's lots easier.

I figured it out

How do you find atomic mass? When it's like CH4

Do you add or multiply they're atomic masses?

What you are asking is no more called relative atomic mass but relative molecular mass in case of a molecule, and the relative formula mass in case of an ion.

To find the molecular mass, just add the relative atomic masses. If there are more than one of the same atom, include each one of the atoms in your relative molecular mass.

Hope it helped!:)