RosSin
Apr 9, 2009, 11:22 PM
Q. Unpolarized light of intensity Io is incident on a stack of 3 polarizers, and intensity I emerges from the last polarizer. If the angles of the three polarizers are 0 degrees, 30 degrees and 70 degrees with respect to vertical what is the ratio I/Io?
A 0.088
B 0.660
C 0.220
D 0.440
E 0.044
Thanks in advance
Perito
Apr 10, 2009, 05:46 AM
Starting with Malus' law, again
I=I_o\,cos^2(\theta)
or
\frac{I}{I_o}=cos^2(\theta)
This time you have two experiments because you have three polarizers. The first pair rotates the light by 30 degrees; the second pair rotates the light by 70 degrees (40 degrees additional). We presume that the same material is present between both sets of polarizers.
So,
\frac{I_1}{I_o}\,=\,cos^2(30)\, =\, 0.75
\frac{I}{I_1}\,=\,cos^2(40)\, =\, 0.587
therefore
\frac{I}{I_o}\,=\,\frac{I_1\,}{\,I_o}\,\frac{I}{I_ 1} \,=\,(0.75)\, (0.587)\,=\,0.440
You could also have solved this in one step:
\frac{I}{I_o}\,=\,cos^2(30)\,cos^2(40)
Your answer is "D".