A ship sailed from Port K to Port L. Port L is located 28km East and 16km South of Port K.
Calculate the distance of KL and the bearing of Port L from Port K.
Give answer correct to 3 significant figures.

This requires only the Pythagorean Theorem:

R^2 = X^2 + Y^2

where X and Y are the two sides of the right triangle and R is the side opposite the 90 degree angle.

Also, the bearing can easily be calculated from the two given distances.

Per the diagram:

@=tan^{-1}(\frac{16}{28})

Do you want a bearing or an azimuth? There is a difference.

An azimuth is an angle turned clockwise off due north. For that, just add the answer from above to 90 degrees.

A bearing is done in quadrants, as in land deeds.

Your bearing would be S[90-(\text{the above answer})]E

The bearing from Port K to L can be calculated from arctan(16/28) - this is the angle south of east, so add 90 degres to get a bearing from north.

Pythagorean Theorem...

The hypotenuse is equivalent to the square root of the sum of the square of both sides.

What is the difference between north 60 degree from 60 dergee northeast

what is the difference between north 60 degree from 60 dergee northeast


:)